#### Bond order of CN cyanide is 2.5

##### **how to find bond order of CN cyanide**

Draw the molecular orbital diagram for CN (cyanide)

total number of electrons in CN (cyanide) is 13

because atomic number of Carbon is 6

and atomic number of nitrogen is 7

add the atomic number of carbon and nitrogen

carbon + nitrogen =13

6+7=13

molecular orbital electronic configuration of Cyanide (CN) ** σ1s², σ*1s², σ2s², σ*2s², π2px²=π2py²**** σ2pz¹** The number of bonding molecular orbital electrons (9) and the number of anti-bonding molecular orbital electrons (4). Subtract the number of anti-bonding electrons from the number of bonding electrons: 9–4 = 5Divide the result by 2: 5/ 2 = 2.5

* So, the bond order of CN (Cyanide) is 2.5** hence it is proved that** The bond order of CN (Cyanide) is 2.5*

if you want to get more information, click here

#### bond order of CN-

**how to find bond order of CN cyanide anion**

Draw the molecular orbital diagram for Cyanide anion (CN-)

total number of electrons in CN- is 14

because atomic number of Carbon is 6

and atomic number of nitrogen is 7

one electron is added to cyanide molecule

molecular orbital electronic configuration of Cyanide anion (CN- **σ1s², σ*1s², σ2s², σ*2s², π2px²=π2py²,****σ2pz²**The number of bonding molecular orbital electrons (10) and the number of anti-bonding molecular orbital electrons (4). Subtract the number of anti-bonding electrons from the number of bonding electrons: 10 – 4 = 6 Divide the result by 2: 6/ 2 = 3

* So, the bond order of CN- (Cyanide anion) is 3**hence it is proved that**The bond order of CN- (Cyanide anion) is 3*

#### bond order of CN+

how to find bond order of CN+ (cyanide cation)

Draw the molecular orbital diagram for CN+ **total number of electrons in CN+ is 12**

because atomic number of Carbon is 6

and atomic number of nitrogen is 7

total electrons in cyanide molecule is 13, but one electrons is removed from cyanide molecule

electronic configuration of Cyanide cation (CN+) **σ1s², σ*1s², σ2s², σ*2s², π2px²=π2py²**

The number of bonding molecular orbital electrons (8) and the number of anti-bonding molecular orbital electrons (4).

Subtract the number of anti-bonding electrons from the number of bonding electrons: 8 – 4 =4

Divide the result by 2: 4/ 2 = **2**

*So, the bond order of CN+ (Cyanide anion) is 2** hence it is proved that** The bond order of CN+ (Cyanide anion) is 2*

if you want to see bond order of O, click here

if you want to see more information about cyanide, click here

## 1 thought on “3 types bond order of CN cyanide”