3 types bond order of CN cyanide

 Bond order of CN cyanide is 2.5

 how to find bond order of CN cyanide

Draw the molecular orbital diagram for CN (cyanide)
total number of electrons in CN (cyanide) is 13
because atomic number of Carbon is 6
and atomic number of nitrogen is 7
add the atomic number of carbon and nitrogen
carbon + nitrogen =13
6+7=13
molecular orbital electronic configuration of Cyanide (CN)   σ1s², σ*1s², σ2s², σ*2s², π2px²=π2py² σ2pz¹ The number of bonding molecular orbital electrons (9) and the number of anti-bonding molecular orbital electrons (4). Subtract the number of anti-bonding electrons from the number of bonding electrons: 9–4 = 5Divide the result by 2: 5/ 2 = 2.5

       So, the bond order of CN (Cyanide) is 2.5
      hence it is proved that
     The bond order of CN (Cyanide) is 2.5

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 bond order of CN-

how to find bond order of CN cyanide anion

Draw the molecular orbital diagram for Cyanide anion (CN-)
total number of electrons in CN- is 14
because atomic number of Carbon is 6
and atomic number of nitrogen is 7
one electron is added to cyanide molecule
molecular orbital electronic configuration of Cyanide anion (CN-  σ1s², σ*1s², σ2s², σ*2s², π2px²=π2py²,σ2pz²The number of bonding molecular orbital electrons (10) and the number of anti-bonding molecular orbital electrons (4). Subtract the number of anti-bonding electrons from the number of bonding electrons: 10 – 4 = 6 Divide the result by 2: 6/ 2 = 3   

 So, the bond order of CN- (Cyanide anion) is 3
hence it is proved that
The bond order of CN- (Cyanide anion) is 3

bond order of CN+

how to find bond order of CN+ (cyanide cation)

Draw the molecular orbital diagram for CN+
total number of electrons in CN+ is 12
because atomic number of Carbon is 6
and atomic number of nitrogen is 7
total electrons in cyanide molecule is 13, but one electrons is removed from cyanide molecule
electronic configuration of Cyanide cation (CN+) σ1s², σ*1s², σ2s², σ*2s², π2px²=π2py²

The number of bonding molecular orbital electrons (8) and the number of anti-bonding molecular orbital electrons (4).

Subtract the number of anti-bonding electrons from the number of bonding electrons: 8 – 4 =4

Divide the result by 2:      4/ 2    = 2

    So, the bond order of CN+ (Cyanide anion) is 2
     hence it is proved that
     The bond order of CN+ (Cyanide anion) is 2

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