# 3 types bond order of O₂

### Bond order of O₂

how to determine bond order of O₂

Draw the molecular orbital diagram for O₂
total number of electrons in O₂ is 16
because atomic number of O is 8
2 atoms of oxygen
2 × 8 = 16
electronic configuration of molecular σ1s², σ*1s²,σ2s², σ*2s², π2px²=π2py² σ2pz², π*2px¹=π*2py¹

Number of bonding electrons orbital (10) and the number of anti-bonding electrons orbital (6).

Subtract the number of anti-bonding electrons from the number of bonding electrons: 10 – 6 = 4

Divide the result by 2: 4 / 2 = 2

So, the bond order of O₂ is 2, indicating a resonance hybrid of a single bond and a double bond, resulting in an average bond order of 2

### bond order of O₂-

how to determine bond order of (oxygen anion) O₂-

1. Draw the molecular orbital diagram for O₂-
total number of electrons in oxygen molecules O₂ is 16
because atomic number of O is 8
2 atoms of oxygen
2 × 8 = 16
but in the case of O₂- one electron is added to the oxygen molecules
the total electrons in oxygen molecule’s anion will be 17 electronic configuration of oxygen molecule’s anion
σ1s², σ*1s²,σ2s², σ*2s², π2px²=π2py²
σ2pz², π*2px²=π*2py¹

Number of bonding electrons orbital (10) and the number of anti-bonding electrons orbital (7).

Subtract the number of anti-bonding electrons from the number of bonding electrons: 10 – 7 = 3

Divide the result by 2:         3 / 2 = 1.5

So, the bond order of O₂- (oxygen molecules anions) 1.5

### bond order of O₂+

how to determine bond order (oxygen cation) of O₂

Draw the molecular orbital diagram for O₂+
total number of electrons in oxygen molecules O₂+ is 15
because atomic number of O is 8
2 atoms of oxygen
2 × 8 = 16
but in the case of O₂+ one electron is removed from oxygen molecules so
the total electrons in oxygen molecules will be 15 electronic configuration of oxygen molecule’s cation (O₂+)
σ1s², σ*1s²,σ2s², σ*2s², π2px²=π2py²
σ2pz², π*2px¹=π*2py
2. Number of bonding electrons orbital (10) and the number of anti-bonding electrons orbital (5).
3. Subtract the number of anti-bonding electrons from the number of bonding electrons: 10 – 5 = 5
4. Divide the result by 2:       5/ 2 = 2.5

So, the bond order of O₂+ (oxygen molecules cation) 2.5